-- 测试当前用户class_id功能的验证脚本

-- 1. 检查ak_users表中用户的class_id设置情况
SELECT 
    id,
    username,
    email,
    role,
    school_id,
    grade_id,
    class_id
FROM public.ak_users 
WHERE role IN ('teacher', 'student')
ORDER BY role, username;

-- 2. 检查每个班级的学生分布
SELECT 
    c.id as class_id,
    c.name as class_name,
    g.name as grade_name,
    s.name as school_name,
    COUNT(u.id) as student_count,
    array_agg(u.username) as student_names
FROM public.ak_classes c
LEFT JOIN public.ak_grades g ON c.grade_id = g.id
LEFT JOIN public.ak_schools s ON g.school_id = s.id
LEFT JOIN public.ak_users u ON u.class_id = c.id AND u.role = 'student'
GROUP BY c.id, c.name, g.name, s.name
ORDER BY s.name, g.name, c.name;

-- 3. 检查是否有用户（老师或学生）分配到了同一个班级
SELECT 
    class_id,
    COUNT(CASE WHEN role = 'teacher' THEN 1 END) as teacher_count,
    COUNT(CASE WHEN role = 'student' THEN 1 END) as student_count,
    array_agg(CASE WHEN role = 'teacher' THEN username END) as teachers,
    array_agg(CASE WHEN role = 'student' THEN username END) as students
FROM public.ak_users 
WHERE class_id IS NOT NULL
GROUP BY class_id
ORDER BY class_id;

-- 4. 模拟前端功能：假设当前登录用户有class_id，查询同班级学生
-- 这里以第一个有class_id的用户为例
WITH current_user_class AS (
    SELECT class_id 
    FROM public.ak_users 
    WHERE class_id IS NOT NULL 
    LIMIT 1
)
SELECT 
    u.id,
    u.username,
    u.role,
    u.class_id,
    c.name as class_name
FROM public.ak_users u
JOIN current_user_class cuc ON u.class_id = cuc.class_id
LEFT JOIN public.ak_classes c ON u.class_id = c.id
WHERE u.role = 'student'
ORDER BY u.username;

-- 5. 检查v_latest_student_health视图是否存在并能正常查询
-- 如果视图不存在，这个查询会报错
SELECT 
    user_id,
    name,
    temperature_c,
    heart_rate_bpm,
    spo2_percent,
    step_count
FROM public.v_latest_student_health 
LIMIT 5;

-- 6. 完整的模拟查询：模拟前端的完整逻辑
-- 假设当前用户的class_id是第一个有class_id的用户
WITH current_user_info AS (
    SELECT id, username, class_id 
    FROM public.ak_users 
    WHERE class_id IS NOT NULL 
    LIMIT 1
),
same_class_students AS (
    SELECT u.id, u.username, u.student_id, u.avatar
    FROM public.ak_users u
    JOIN current_user_info cui ON u.class_id = cui.class_id
    WHERE u.role = 'student'
)
SELECT 
    scs.id,
    scs.username,
    scs.student_id,
    vh.temperature_c,
    vh.heart_rate_bpm,
    vh.spo2_percent,
    vh.step_count,
    -- 模拟异常判断
    CASE 
        WHEN vh.temperature_c < 36.0 OR vh.temperature_c > 37.5 THEN 1 
        ELSE 0 
    END +
    CASE 
        WHEN vh.heart_rate_bpm < 60 OR vh.heart_rate_bpm > 100 THEN 1 
        ELSE 0 
    END +
    CASE 
        WHEN vh.spo2_percent < 95 THEN 1 
        ELSE 0 
    END as abnormal_count
FROM same_class_students scs
LEFT JOIN public.v_latest_student_health vh ON scs.id = vh.user_id
ORDER BY 
    -- 异常优先排序
    (CASE 
        WHEN vh.temperature_c < 36.0 OR vh.temperature_c > 37.5 THEN 1 
        ELSE 0 
    END +
    CASE 
        WHEN vh.heart_rate_bpm < 60 OR vh.heart_rate_bpm > 100 THEN 1 
        ELSE 0 
    END +
    CASE 
        WHEN vh.spo2_percent < 95 THEN 1 
        ELSE 0 
    END) DESC,
    scs.username;