152 lines
6.4 KiB
SQL
152 lines
6.4 KiB
SQL
-- 通过ak_users的名字反查学生所在的部门数组，并映射到班级ID
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-- 处理member_user表中的dept_ids数组字段，通过system_dept的name字段进行映射
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-- 方案1: 基础查询 - 处理dept_ids数组，通过system_dept.name进行映射
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SELECT
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au.id as ak_user_id,
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au.username as student_name,
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au.email as ak_email,
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mu.dept_ids as original_dept_ids,
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unnest(mu.dept_ids) as dept_id, -- 展开数组
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sd.name as dept_name, -- 这是真正的条件字段
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sd.id as dept_table_id,
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mu.name as original_name,
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mu.email as original_email,
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-- 通过system_dept.name字段进行班级ID映射
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CASE
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WHEN sd.name = '2022001' THEN 'bc333301-78cd-4ef0-a123-456789012345'::uuid
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WHEN sd.name = '2022002' THEN 'bc333302-78cd-4ef0-a123-456789012345'::uuid
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WHEN sd.name = '2022003' THEN 'bc333303-78cd-4ef0-a123-456789012345'::uuid
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WHEN sd.name = '2022004' THEN 'bc333304-78cd-4ef0-a123-456789012345'::uuid
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WHEN sd.name = '2022005' THEN 'bc333305-78cd-4ef0-a123-456789012345'::uuid
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WHEN sd.name = '2022006' THEN 'bc333306-78cd-4ef0-a123-456789012345'::uuid
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ELSE NULL
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END as mapped_class_id
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FROM public.ak_users au
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LEFT JOIN public.member_user mu ON au.username = mu.name
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LEFT JOIN LATERAL unnest(mu.dept_ids) AS dept_id ON true
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LEFT JOIN public.system_dept sd ON dept_id = sd.id
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WHERE au.role = 'student'
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AND mu.dept_ids IS NOT NULL
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ORDER BY au.username;
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-- 方案2: 使用子查询处理数组 - 通过system_dept.name进行映射
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WITH dept_expanded AS (
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SELECT
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au.id as ak_user_id,
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au.username as student_name,
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mu.name as original_name,
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mu.dept_ids as original_dept_ids,
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dept_id,
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sd.name as dept_name, -- 这是映射的关键字段
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sd.id as dept_table_id
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FROM public.ak_users au
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LEFT JOIN public.member_user mu ON au.username = mu.name
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LEFT JOIN LATERAL unnest(mu.dept_ids) AS dept_id ON true
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LEFT JOIN public.system_dept sd ON dept_id = sd.id
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WHERE au.role = 'student' AND mu.dept_ids IS NOT NULL
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)
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SELECT
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ak_user_id,
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student_name,
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original_name,
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array_agg(dept_name) as all_dept_names, -- 显示所有部门名称
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array_agg(dept_table_id) as all_dept_ids,
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-- 通过dept_name进行班级映射，优先选择第一个匹配的
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CASE
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WHEN '2022001' = ANY(array_agg(dept_name)) THEN 'bc333301-78cd-4ef0-a123-456789012345'::uuid
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WHEN '2022002' = ANY(array_agg(dept_name)) THEN 'bc333302-78cd-4ef0-a123-456789012345'::uuid
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WHEN '2022003' = ANY(array_agg(dept_name)) THEN 'bc333303-78cd-4ef0-a123-456789012345'::uuid
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WHEN '2022004' = ANY(array_agg(dept_name)) THEN 'bc333304-78cd-4ef0-a123-456789012345'::uuid
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WHEN '2022005' = ANY(array_agg(dept_name)) THEN 'bc333305-78cd-4ef0-a123-456789012345'::uuid
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WHEN '2022006' = ANY(array_agg(dept_name)) THEN 'bc333306-78cd-4ef0-a123-456789012345'::uuid
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ELSE NULL
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END as mapped_class_id
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FROM dept_expanded
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GROUP BY ak_user_id, student_name, original_name
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ORDER BY student_name;
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-- 方案3: 直接更新ak_users表 - 通过system_dept.name进行映射
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UPDATE public.ak_users
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SET class_id = dept_mapping.mapped_class_id
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FROM (
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WITH dept_expanded AS (
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SELECT
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au.id as ak_user_id,
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sd.name as dept_name -- 使用dept_name进行映射
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FROM public.ak_users au
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LEFT JOIN public.member_user mu ON au.username = mu.name
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LEFT JOIN LATERAL unnest(mu.dept_ids) AS dept_id ON true
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LEFT JOIN public.system_dept sd ON dept_id = sd.id
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WHERE au.role = 'student' AND mu.dept_ids IS NOT NULL
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)
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SELECT
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ak_user_id,
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CASE
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WHEN dept_name = '2022001' THEN 'bc333301-78cd-4ef0-a123-456789012345'::uuid
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WHEN dept_name = '2022002' THEN 'bc333302-78cd-4ef0-a123-456789012345'::uuid
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WHEN dept_name = '2022003' THEN 'bc333303-78cd-4ef0-a123-456789012345'::uuid
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WHEN dept_name = '2022004' THEN 'bc333304-78cd-4ef0-a123-456789012345'::uuid
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WHEN dept_name = '2022005' THEN 'bc333305-78cd-4ef0-a123-456789012345'::uuid
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WHEN dept_name = '2022006' THEN 'bc333306-78cd-4ef0-a123-456789012345'::uuid
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ELSE NULL
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END as mapped_class_id
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FROM dept_expanded
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WHERE dept_name IN ('2022001', '2022002', '2022003', '2022004', '2022005', '2022006')
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-- 如果一个学生属于多个相关部门，按优先级选择
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ORDER BY ak_user_id,
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CASE dept_name
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WHEN '2022001' THEN 1
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WHEN '2022002' THEN 2
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WHEN '2022003' THEN 3
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WHEN '2022004' THEN 4
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WHEN '2022005' THEN 5
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WHEN '2022006' THEN 6
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ELSE 999
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END
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) dept_mapping
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WHERE ak_users.id = dept_mapping.ak_user_id
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AND dept_mapping.mapped_class_id IS NOT NULL;
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-- 方案4: 查看数组字段和部门名称统计
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SELECT
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sd.name as dept_name,
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COUNT(DISTINCT au.id) as student_count,
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array_agg(DISTINCT au.username) as sample_students
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FROM public.ak_users au
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LEFT JOIN public.member_user mu ON au.username = mu.name
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LEFT JOIN LATERAL unnest(mu.dept_ids) AS dept_id ON true
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LEFT JOIN public.system_dept sd ON dept_id = sd.id
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WHERE au.role = 'student' AND mu.dept_ids IS NOT NULL
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GROUP BY sd.name
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ORDER BY sd.name;
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-- 方案5: 检查包含特定部门名称的学生
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SELECT
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au.username,
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array_agg(sd.name) as dept_names, -- 显示所有相关的部门名称
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CASE
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WHEN '2022001' = ANY(array_agg(sd.name)) THEN '初三(1)班'
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WHEN '2022002' = ANY(array_agg(sd.name)) THEN '初三(2)班'
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WHEN '2022003' = ANY(array_agg(sd.name)) THEN '初三(3)班'
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WHEN '2022004' = ANY(array_agg(sd.name)) THEN '初三(4)班'
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WHEN '2022005' = ANY(array_agg(sd.name)) THEN '初三(5)班'
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WHEN '2022006' = ANY(array_agg(sd.name)) THEN '初三(6)班'
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ELSE '未分配班级'
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END as target_class_name
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FROM public.ak_users au
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LEFT JOIN public.member_user mu ON au.username = mu.name
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LEFT JOIN LATERAL unnest(mu.dept_ids) AS dept_id ON true
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LEFT JOIN public.system_dept sd ON dept_id = sd.id
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WHERE au.role = 'student'
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AND mu.dept_ids IS NOT NULL
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GROUP BY au.username
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HAVING
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'2022001' = ANY(array_agg(sd.name)) OR
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'2022002' = ANY(array_agg(sd.name)) OR
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'2022003' = ANY(array_agg(sd.name)) OR
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'2022004' = ANY(array_agg(sd.name)) OR
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'2022005' = ANY(array_agg(sd.name)) OR
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'2022006' = ANY(array_agg(sd.name))
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ORDER BY au.username;
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